make a sketch and place (2,-3) into the fourth quadrant. Complete the right-angled triangle
the hypotenuse will be √13 , x - 2, y = -3
let the angle be Ø
tanØ = -3/2
Ø = 2π - .98279.. = 5.3
so one point is (√13, 5.3) which is what you have.
your other point is also correct.
for the point (a,3a) , a > 0 , the point is in quad I
tanØ = 3a/a = 3
Ø = 1.25 , you are right
r = √(a^2 + 9a^) = a√10 = appr 3.16a
again, you are right, good job
I don't understand how to do these problems:
Find two pairs of polar coordinates for each point with the given rectangular coordinates if 0 ≤ θ ≤ 2π. Round to the nearest hundredth, if necessary.
17. (2, -3)
Answers: (3.61, 5.30) and (-3.61, 2.16)
19. (a, 3a), a > 0
Answers: (3.16a, 1.25) and (-3.16a, 4.39)
Thank you!!
1 answer
1 answer