I assume you meant
7(x-2)^5 < 0
so (x-2)^5 < 0
we know (any negative)^5 < 0
so x-2 < 0
or
x < 2
I don't remember how to solve this.
The question is: For what values of a is the expression 7(x-2)5 negative? Write answer using interval notation.
4 answers
oops sorry. it's actually
For what values of a is the expression 7(x-2)-5 negative?
For what values of a is the expression 7(x-2)-5 negative?
That's even easier
7(x-2) - 5 < 0
7x - 14 - 5 < 0
7x < 19
x <19/7
7(x-2) - 5 < 0
7x - 14 - 5 < 0
7x < 19
x <19/7
Ok so I did it correctly. Thank you