pH+pOH=14
since,
pH=-log[H+]
pOH=-log[OH-]
therefore,
[H+]=10^(-pH)
[OH-]=10^(-pOH]
I don't know why on earth I don't remember how to do this, but I can't, and it's so simple.
Calculate [H+] and [OH-] of a solution with a pH of 9.7
Thank you.
1 answer