You need to understand colligative properties.
freezing pt depression=-molality*.52
solve for the concentration in molalities.
I don't know how to answer this. An aqueous solution of glucose has a freezing point of -0.37. What is the concentration of the solution?
2 answers
Decrease in freezing temperature caused by glucose= 0°C-(-0.37)= 0.37°C
∆T_f= K_f x m
0.37°C= 1.86°C x m
m= 0.37°C/ 1.86°C
= 0.2 mole of glucose in 1kg water
∆T_f= K_f x m
0.37°C= 1.86°C x m
m= 0.37°C/ 1.86°C
= 0.2 mole of glucose in 1kg water
1 answer