clearly, since they are all on the same rigid platform, their rotational periods are all the same.
Since the circumference is just a constant times the radius, their speeds are in the same proportion as their radii. Someone 1/2 as far out is going 1/2 as fast.
since the radial acceleration is v^2/r, someone twice as far out (2r) will have
a = (2v)^2/(2r) = 2(v^2/r)
or, twice the acceleration.
I don't completely understand what this question is asking:
Three people are standing on a horizontally rotating platform in an amusement park. One person is almost at the edge, the second one is (3/5)R from the center, and the third is (1/2)R from the center. Compare their periods of rotation, their speeds, and their radial accelerations.
I don't know how to find all that with the information given can someone explain what I'm suppose to do?
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What are the #s for the problem .. like what is v what is r
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