i did my question already but i was wondering if someone could double check my work.

Question

the question says to graph the following function on the grpah
f(x)={|x|, -3 is equal to or less than x less than 2}
{2x-8, x less than or equal to 2}
i dont know if its possible to show a graph but mine has 2 functions. a v shaped one and liner one.they dont intercept and the liner one is below the v-shaped one

my x vales for 2x-8 were -2, -1, 0, 1, and 2. my y values were -12, -10, -8, -6, and -4

for |x| my x values are -2, -1, 0, 1, and 2. my y values are 2, 1, 0, 1, and 2.

the next part says to evaluate
F(0), i got |0| which equals 0
f(10), i did 2(10)-8 which equals 12

hope you can check it with this info

Answer 1

Everything you've mentioned is correct.

You might check that the boundaries are shown correctly:
The absolute value graph should have a solid circle at (-3, 3) and an open circle at (2, 2).
The linear function should have an arrow on the downward-left end and a solid circle at (2, -4).