I could really use the help on this as soon as possible.

what is the slope of the line tangent to the curve (/x)^2 at point (4,16)

2 answers

check your typing.

Your curve would have an equation of the form
y = .... or f(x) = ....

secondly, (/x^2) is missing its numerator.
its the squareroot of x squared
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