it's a lot easier without all those words:
(x/2)^3 * (x/2)^4
----------------------
((x/2)^3)^2
= (x/2)^7 / (x/2)^6
= x/2
Hmmm. Not what you want. I suspect a typo somewhere.
I can't quite write the problem, so I'll try to explain it as best I can. In exponents and in fractions...
(X/2) to the 3rd power times (X/2) to the 4th power...all over,or divided by, (X/2 to the 3rd power) to the 2nd power.
The book says the answer is X/2 to the 5th power. How is this answer found???? I keep getting X/2 to the 6th power ☹️
4 answers
Since they are all the same, let x represent x/2. Online "^" is used to indicate an exponent, e.g., x^2 = x squared
(x^3 * x^4)/(x^3)^2
When multiplying/dividing, exponents are added/subtracted respectively.
(x^3 * x^4) = x^7
(x^3)^2 = x^6
Do you have typos?
(x^3 * x^4)/(x^3)^2
When multiplying/dividing, exponents are added/subtracted respectively.
(x^3 * x^4) = x^7
(x^3)^2 = x^6
Do you have typos?
Let me try writing it again...
(X/2)^3*(X/2)^4
---------------------
(X/2^3)^2
How do you get X/2^5????
(X/2)^3*(X/2)^4
---------------------
(X/2^3)^2
How do you get X/2^5????
I don't. I still get:
(x/2)^7/(x/2)^6 = x/2
If you do not have a typo, there might be a typo in the text answers. Ask your teacher.
(x/2)^7/(x/2)^6 = x/2
If you do not have a typo, there might be a typo in the text answers. Ask your teacher.
3 answers