This is a simple stoichiometry problem. Here are the steps. You need to learn how to solve them. Remember the steps.This will work 75% of the problems you have in beginning chemistry. With a few modifications it will work many more than that.
Step 1. Write and balance the equation. You've done that.
Step 2. Convert what you have into mols. mols H2 = grams/molar mass = 4/2 = 2
Step 3. Using the coefficients in the balanced equation, convert mols of what you have to mols of what you want.
2 mols H2 x (1 mol CH3OH/2 mols H2) = 1 mol CH3OH
Step 4. Now convert to grams. grams CH3OH = mols CH3OH x molar mass CH3OH = 1 x 32 = 32 g
REMEMBER the steps for doing this. It will save you a lot of heartache down the road.
I can't get this!
If 4.00 g of H2 are made to react with excess CO(g) how many grams of CH3OH(l) can theoretically be produced according to the following equation?
CO(g) + 2H2(g) → CH3OH(l)
1 answer
1 answer