I burned a candle for 3 minutes. It started with a mass of 38.53g (C25H52). It ended with a mass of 38.48g. What mass of water was produced in three minutes? If I burned the candle all day, what mass of the candle would react?

Answer 1

38.53-38.48 = 0.05 gram of C25H52 that burned.
Convert 0.05 g C25H52 to moles. Moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles C25H52 to moles H2O.
Convert moles H2O to grams. grams = moles x molar mass.

Answer 2

would the answer for the first question be .06654 g H2O?

Answer 3

I obtained 0.065 g but I think we're allowed only one sig figure.

Answer 4

What would be the answer to the second question then?