You added how may mols NaOH? That's M x L = mols.
What final volume do you have. You added 18.01 mL and 10 mL so total volume is 28.01 mL. Convert that to L., then M = mols/L
I am trying to complete a lab called Precipitation Titration of Cobalt Chloride. I've done the experiment and I got that if you combine 18.01mL of 0.1M NaOH with 10mL of CoCl2, the precipitate is forms. Now how do I calculate the concentration of the amount of NaOH I added? Please help.
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