You do not have enough of one or the other, limiting the amount of Cu resulting.
Use the one you do not have enough of. Your mols of Al must be at least 2/3 the number of mols of CuCl....... If it is less use it. If it is more use the CuCl ... and you will have some Al left over
I am supposed to calculate the theoretical mass and moles of Cu. However I am given the mass of 2 reactants in the balanced equation:
3CuCl2*2H2O + 2Al -> 3Cu + 2AlCl3 + 6H2O
I am given the mass of CuCl2*2H2O to be 0.477g and the mass of Al is 0.267g. If I wanted to calculated the theoretical moles and mass of Cu produced which one do I use? The mass with the Cu or the mass of the Al? I tried using both of them by converting them to moles and then to the ratio of mole from the balanced equation but got two different results. One must be incorrect and one must be correct. Help please?
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