Dr Bob answered your question earlier this evening... He wrote...
diatance = rate x time.
It took t1 to go there so d1 = 14*t1
It took t2 to get back and you know t1 + t2 = 3.4 hours.
distance there = 14*t1
distance back = 20*t2. Since the distance is the same, then
14(t1 = 20*t2 and you know
t1 + t2 = 3.4 hours.
Solve those two equation fort1 and t2 like this.
14*t1 = 20*(3.4-t1)
I get t1 = 2.0 hours and t2 = 1.4 hours.
Then use either distance equation above to find d; i.e.,
14*t1 = 14 x 2.0 = ? miles.
I am stumped on this question which I belive I will never get an answer to it
Shelly hopped onto her bicycle and pedaled to the park at 14 miles per hour. Then she whizzed back at 20 miles per hour. If the total trip took 3 2/5 hours how far was it to the park?
if someone can explain how to do it??
I took 14mph and 20mph and added it and got 34mph. Then I took 3 2/5(which is 3.4 as a decimal) and divided it with the total mph (34÷3.4) and got 10miles
(idk if that is even right)
so now how do i figure out how far it took one way to the park?????
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1 answer