expanded it would be
if n = 2 I get 13
if n = 3 I get 18
if n = 4 I get 23
if n = 5 I get 28
that sum is 82, not 85
i AM STUCK TRYING TO FIGURE THIS PROBLEM. SUMMATION NOTATION.
5 OVER A SIDEWAYS Z AT THE BOTTOM THERE IS N=2 AND ON THE SIDE THERE IS (5N+3) I came up with the answer 85
3 answers
could you please show how you worked thid problem
I thought I just did.
n takes on integer values from n=2 to n=5
those values are subbed into the given expression 5n+3, they are then added.
so..
[sigma] (5n+3) from n=2 to n=5
= 13+18+23+28
= 82
n takes on integer values from n=2 to n=5
those values are subbed into the given expression 5n+3, they are then added.
so..
[sigma] (5n+3) from n=2 to n=5
= 13+18+23+28
= 82