I am stuck on this problem that I have tried to solve so many times! The question is:The length of a rectangle is four more than twice the width. If the perimeter of the rectangle is 32 cm, what are the length and width of the rectangle?

Here is my work:
32=2(2x+4)+2(2w)
32=(4w+8)+(4w)
32= 8w+8
32-8=8w+8-8
24=8w
24/8=8w/8
w=3
l=10
The work seems correct to me but when I check the answer it's wrong! What am I doing wrong?

1 answer

P = 2L + 2W

32 = 2(2W + 4) + 2W

32 = 6W + 8

24 = 6W

4 = W