Asked by Mick
I am stuck on this problem that I have tried to solve so many times! The question is:The length of a rectangle is four more than twice the width. If the perimeter of the rectangle is 32 cm, what are the length and width of the rectangle?
Here is my work:
32=2(2x+4)+2(2w)
32=(4w+8)+(4w)
32= 8w+8
32-8=8w+8-8
24=8w
24/8=8w/8
w=3
l=10
The work seems correct to me but when I check the answer it's wrong! What am I doing wrong?
Here is my work:
32=2(2x+4)+2(2w)
32=(4w+8)+(4w)
32= 8w+8
32-8=8w+8-8
24=8w
24/8=8w/8
w=3
l=10
The work seems correct to me but when I check the answer it's wrong! What am I doing wrong?
Answers
Answered by
Ms. Sue
P = 2L + 2W
32 = 2(2W + 4) + 2W
32 = 6W + 8
24 = 6W
4 = W
32 = 2(2W + 4) + 2W
32 = 6W + 8
24 = 6W
4 = W
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