I am stuck on this problem that I have tried to solve so many times! The question is:The length of a rectangle is four more than twice the width. If the perimeter of the rectangle is 32 cm, what are the length and width of the rectangle?

Question

Here is my work:
32=2(2x+4)+2(2w)
32=(4w+8)+(4w)
32= 8w+8
32-8=8w+8-8
24=8w
24/8=8w/8
w=3
l=10
The work seems correct to me but when I check the answer it's wrong! What am I doing wrong?

Answer 1

P = 2L + 2W

32 = 2(2W + 4) + 2W

32 = 6W + 8

24 = 6W

4 = W