I am struggling with absolute value functions, especially equations. I need help with these questions:
1. |x^2 - 2x - 3| - 4
2. | x^2 - 2x| = 1
7 answers
I'm really sorry but I was hoping that I could get some help with this question but I am not recieving any help from anyone. I am struggling a lot.....
People are deleting my comments and my questions that I have and I'm not happy about that. Everyone needs help.
Please be patient. I haven't seen a math tutor on Jiskha since you posted this 20 minutes ago.
@Ms. Sue
Ok
Ok
We are all volunteers on here, I just got in , so ....
your first question is not an equation, so you will have to fix it
your 2nd:
| x^2 - 2x| = 1
± (x^2 - 2x) = 1
x^2 - 2x = 1 OR -x^2 + 2x = 1
x^2 - 2x - 1 = -0
x (2 ± √8/2 = 1 ± √2
or
x^2 - 2x + 1 = 0
(x - 1)^2 = 0
x-1 = 0
x = 1
after you fix your first one, do it the same way as #2
your first question is not an equation, so you will have to fix it
your 2nd:
| x^2 - 2x| = 1
± (x^2 - 2x) = 1
x^2 - 2x = 1 OR -x^2 + 2x = 1
x^2 - 2x - 1 = -0
x (2 ± √8/2 = 1 ± √2
or
x^2 - 2x + 1 = 0
(x - 1)^2 = 0
x-1 = 0
x = 1
after you fix your first one, do it the same way as #2
@Reiny
The first equation is:
0= |x^2 - 2x - 3| - 4
The first equation is:
0= |x^2 - 2x - 3| - 4
So it is just like the 2nd, which I did for you
0= |x^2 - 2x - 3| - 4
|x^2 - 2x - 3| = 4
x^2 - 2x - 3 = 4 OR -x^2 + 2x + 3 = 4
solve each quadratic
both of them have real answers.
0= |x^2 - 2x - 3| - 4
|x^2 - 2x - 3| = 4
x^2 - 2x - 3 = 4 OR -x^2 + 2x + 3 = 4
solve each quadratic
both of them have real answers.