do vertical and horizontal problems separately
Vertical
Just plain fall, no initial velocity up or down
so a)
10 = (1/2)(9.81) t^2
b)
use that t to find out how far away he landed
d = u t = 1.2 t
c)
vertical v = g t = 9.81 t
horizontal u = 1.2
speed = sqrt (u^2+v^2)
direction
tan angle below horizontal = |v|/u
I am so lost and confused right now with this question. I might have a quiz. Help me understand before this pop quiz!!!! THANKYOU
A diver runs horizontally with a speed of 1.2 m/s off a platform that is 10.0 meters above the water.
a) how long before the diver hits the water?
b.) at what horizontal position from the end of the diving board does he hit the water?
c.) what is the diver's velocity just before hitting the water?
1 answer
2 answers