I am reposting my question. Thank you Bob for explaining how to write it..

In ASCII format:

(8x^2y^0z^6)2^ + 3x^2z^12 + 5y^0z^12

64x4^y2^z8^ + 3x2^ + z12^ + 5y0^z12^

64x6^ + 5y2^ + z32^

Please let me know if these makes sense now. Thank you

1 answer

8x^2y^0z^6)2^ + 3x^2z^12 + 5y^0z^12

64x4^y2^z8^ + 3x2^ + z12^ + 5y0^z12^ No. the first term y will be at the zero power (O x 2=0) Z will be to the 12th power (6x2=12)
do that, then gather terms.
Similar Questions
  1. Hello, I am reposting with correct ASCII format with my answer:(4x^5y^6z)2^ X (5x^9y^12z)3^ (16x^7y^8z^2) X (125x^12y^15z3^)
    1. answers icon 1 answer
  2. We'll choose the word "HOP".Step 2: Convert to ASCII Values Convert each character of "HOP" to its corresponding ASCII value: H:
    1. answers icon 1 answer
  3. We'll choose the word "HOP".Step 2: Convert to ASCII Values Convert each character of "HOP" to its corresponding ASCII value: H:
    1. answers icon 1 answer
  4. Let's walk through the RSA decryption process for the given steps.Step 1: Select a Case-Sensitive Word We'll choose the word
    1. answers icon 1 answer
more similar questions