What is the base of your logarithms?
If it is common logarithm logx=log₁₀x=3.5829 =>
x=10³•⁵⁸²⁹=3827.366
If it is binary logarithm
logx=log ₂x=3.5829
x=2³•⁵⁸²⁹=11.983.
If it is natural logarithm logx=log⒠x=3.5829,
x=e³•⁵⁸²⁹=2.71828³•⁵⁸²⁹=35.978.
I am really struggling with these questions. Any help is appreciated.
Approximate x to three decimal places.
log x = 3.5829
log x = 0.6703
log x = −1.5959
1 answer
1 answer