95% = mean ± 1.96 SEm
SEm = SD/√n
I am not sure how to even get started on this question could someone help please.
A college advisor wants to estimate the mean annual income of all college students who graduated last year. It is believed that the incomes follow a normal distribution with population standard deviation of $2000. Based on a sample of 25 college graduates, the advisor obtains X=$22500. Construct a 95% confidence interval for the population mean u.
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1 answer