-->1 2 3 4 5 6
1 ----- *
2 ----*
3 --*
4 *
5
6
36 possible outcomes
get 5 from four of them
so p = 4/36 = 1/9
(1/9)180 = 20 times
I am lost. How do I figure this out? I know there are 2 ways to get the sum of 5 but do I count it backwards too? 1+4 4+1. How do I know how many sums?
Joe rolled two fair number cubes that have faces labeled 1 to 6 each.
He rolled the two cubes 180 times. According to the theoretical probability,
how many of the rolls should Joe expect the sum to be 5?
1 answer