(A) 428nm/20knot = 21.4 hr
the direction does not matter. You have a distance and a speed.
(B)
E: 20*12 sin 1.4°
S: 20*12 cos 1.4°
(C) Surely the same heading (not bearing!) as the yacht, no?
Ignoring water currents and winds aloft.
I am having trouble with this question.
A privately owned yacht leaves a dock in Myrtke Beach, South Carolina, and heads toward Freeport in the Bahamas at a bearing of S 1.4 degrees E. The yacht averages a speed of 20 knots over the 428-nautical- mile trip.
A. How long will it take the yacht to make the trip?
B. How far east and south is the yacht after 12 hours?
C. A plane leaves Myrtle Beach to fly to Freeport. What bearing should be taken?
I have no idea how to do B and C or where to even begin but for A I got:
20(428/sin1.4), 97 minutes
1 answer
1 answer