heat lost by Cu + heat gained by water + heat gained by calorimeter = 0
[massCu x specific heat Cu x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] + [10 x (Tfinal-Tinitial)] = 0
Solve for Tfinal, the only unknown.
I am having a horrible time with Enthalpy change. I understand how to find specific heat I believe, but the heat capacity of the vessel is given as 10 J/K. My problem is that my professor did not show us how to work this type of problem, and I desperately need help with it. Here is the following problem. I am trying to find the final temperature of the system. I feel like I am missing something, PLEASE HELP!
A 670. g piece of copper tubing is heated to 97.1°C and placed in an insulated vessel containing 57.5 g of water at 40.0°C. Assuming no loss of water and heat capacity for the vessel of 10.0 J/K, what is the final temperature of the system (c of copper = 0.387 J/g·K)?
2 answers
Thankyou, that helped so much.
1 answer