since angles E and F are congruent, the sides opposite them (DF and DE) are congruent. That means that
4x-6 = 2x+8
x = 7
Now you can figure the perimeter.
I am given triangle EDF with angles E and F being congruent. What is the perimeter of the triangle if ED= 2x+8, EF= 3x-6, and DF= 4x-6.
1 answer
1 answer