I am five digit number greater than 40,000 but less than 70,000.My ones digit is more than my ten thousands digit.All my other digit are the same.The sum of my gigit is 19.What number am i?

Answer 1

The fifth digit can only be 4,5, or 6

let's start with the largest case
6X,XX7 , where X is the same
6 + 3x + 7 = 19
3x = 6
X = 2
one case: 62227

if the unit digit is k, it should be clear that
19-(6+k) must be a multiple of 3
and that is true only of x = 2

how about starting with 5
5XXX6 or 5XXX6 etc
again: 19 - (5+K) or 14-k has to be a multiple of 3 and k>5
how about k = 8, which would give us
5XXX8, and 5+3x+8 = 19 ----> X = 1
second case: 51118

last possible case:
4XXX5, or 4XXX6, or 4XXX7 etc
19-(4+k) or 15-k has to be a multiple of 3, and k > 4
k = 9 would work
then 4+ 3X + 9 = 19 -----> X = 2
third case: 42229

Three numbers work:

62227
51118
42229