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I am bit of confused from this question. I have shown the work below and to subtract, am I supposed to be X2 - X1, Y2-Y1, Z2-Z1...Asked by Jake
I am bit of confused from this question. I have shown the work below and to subtract, am I supposed to be X2 - X1, Y2-Y1, Z2-Z1? or X1-X2, Y1-Y2, Z1-Z2?
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A triangle has sides formed by the vectors PA=(2,7,3) and PB=(6,2,2). The point P=(1,3,2). Determine the coordinates of the vertices.
Here is what I have done.
PA-P=(2,7,3)-(1,3,2)
=(-1,-4,-1)
PB-P=(6,2,2) - (1,3,2)
=(-5,1,0)
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A triangle has sides formed by the vectors PA=(2,7,3) and PB=(6,2,2). The point P=(1,3,2). Determine the coordinates of the vertices.
Here is what I have done.
PA-P=(2,7,3)-(1,3,2)
=(-1,-4,-1)
PB-P=(6,2,2) - (1,3,2)
=(-5,1,0)
Answers
Answered by
Reiny
We used to write vectors with [ ] brackets to avoid confusion with points
let point A be (a,b,c), point P is (1,3,2)
then vector PA = [a-1 , b-3 , c-2) = [2 , 7 , 3]
a-1 = 2 ---> a = 3
b-3 = 7 ---> b = 10
c-2 = 3 ---> c = 5
check: for A(3,10,5) and P(1,3,2)
vector PA = [2,7,3]
do the other in the same way
let point A be (a,b,c), point P is (1,3,2)
then vector PA = [a-1 , b-3 , c-2) = [2 , 7 , 3]
a-1 = 2 ---> a = 3
b-3 = 7 ---> b = 10
c-2 = 3 ---> c = 5
check: for A(3,10,5) and P(1,3,2)
vector PA = [2,7,3]
do the other in the same way
Answered by
Jake
Why add?
Answered by
Reiny
Where do you see me adding.
in
vector PA = [a-1 , b-3 , c-2} = [2 , 7 , 3]
I even showed my subtraction of the numbers very explicitly.
Furthermore in my check to prove my answer is correct, you can see that I subtracted the values to get the original vector [2,7,3]
in
vector PA = [a-1 , b-3 , c-2} = [2 , 7 , 3]
I even showed my subtraction of the numbers very explicitly.
Furthermore in my check to prove my answer is correct, you can see that I subtracted the values to get the original vector [2,7,3]
Answered by
Jake
Sorry for the confusion. May I ask why my answer does not work? :S its asking for the vertices, not equal to Point P.
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