h(t) is just a parabola. The max height is reached at the vertex. For the parabola
ax^2 + bx + c
the vertex is at x = -b/2a.
So, for h(t), the vertex is at t = 3.
h(3) = 152
It hits the ground when h=0. To find that, just use the quadratic formula.
I am a parent trying help my son, who has trouble understanding and remembering how to work his math. I never had this math, so it is hard for me to explain it. If I see it worked out. Then I can explain it, (I Think) here is the problems. A ball is tossed into the air and it is modeled by the function h(t)=-16t^2+96t+8. This has a maximum height of? Also need to find the time it would return to the ground?
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