I am a number between 400 and 500. My ones digit is 3 more than my tens digit. The sum of my digits is 13. What number am I?

4 answers

436.

The hundreds must be a four, so the sum of the rest is 13-4=9.

Let x be tens. That gives:
x+(3+x) = 9
x=6

Find ones: 9-6=3.
Amendment (I seem to be doing that a lot when solving problems in my head)

x is, of course 6/2= 3 and represents the tens.

Ones are 9-3=6.
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