27
Because 2+7 = 9 and 7-2 = 5
i am a number between 22 and 30 the sum of my digit 9 and different is 5 who am i?
4 answers
a = First number
b = Second number
The sum of digit = 9
a + b = 9 Subtract b to both sides
a + b - b = 9 - b
a = 9 - b
The different of digit = 5
b - a = 5
b - ( 9 - b ) = 5
b - 9 + b = 5
2 b - 9 = 5 Add 9 to both sides
2 b - 9 + 9 = 5 + 9
2 b = 14 Divide both sides by 2
2 b / 2 = 14 / 2
b = 7
a = 9 - b = 9 - 7 = 2
27
b = Second number
The sum of digit = 9
a + b = 9 Subtract b to both sides
a + b - b = 9 - b
a = 9 - b
The different of digit = 5
b - a = 5
b - ( 9 - b ) = 5
b - 9 + b = 5
2 b - 9 = 5 Add 9 to both sides
2 b - 9 + 9 = 5 + 9
2 b = 14 Divide both sides by 2
2 b / 2 = 14 / 2
b = 7
a = 9 - b = 9 - 7 = 2
27
i am number between 35 and 45 i am completeli divisible by 13 find the number
39 = 3 * 13
1 answer