i am 11 less than the product of 7 and 5. i am 5 more than the product of 11 and 2

Answer 1

I'm not so sure if the problem requires the domain (all possible values of the number). Or if the problem requires only one value of the unknown.
Let x be the number.
From the first statement,
x < 7 * 5 - 11
x < 35 - 11
x < 24
From the second statement,
x > 11 * 2 + 5
x > 22 + 5
x > 27

Thus, if the the domain of x is the one required:
(-infinity, 24) U (27, +infinity)
However, if the problem wants a single value of x, the value does not exist because there is no value that is less than 24 which is, at the same, time must be greater than 27, or
(-infinity, 24) ∩ (27, +infinity) = d.n.e.

Hope this helps~ :)

Answer 2

IGNORE THE ABOVE POST LOL. I shouldn't have used greater than and less than signs! @_@

From the first statement,
x = 7 * 5 - 11
x = 35 - 11
x = 24
From the second statement,
x = 11 * 2 + 5
x = 22 + 5
x = 27

Sorry about that. I don't know what I'm thinking lol. ^^;
Hope this helps~ :)