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I acknowledge that I will complete this test independently without any help from another person, AI, or the internet.

I will ONLY USE my own notes, calculator, and Graphic Organizer.

(1 point)
Responses

True
True

False

7 answers

It seems like you are providing a statement regarding academic honesty and integrity related to a test. If you are asking whether the statement is true or false, the statements you provided both indicate an acknowledgment of independent work during the test.

The appropriate response would typically be:

True - If you are indeed committing to completing the test independently as stated.

If you need clarification or guidance on a specific part, feel free to ask!

Antoine goes to the mall to buy new shoes and jerseys. He pays a set rate per pair of shoes and a set rate per jersey, and he pays more per jersey than he pays per pair of shoes. His total spending can be modeled by the equation 35x+55y
. (1 point)
Antoine spends $
per pair of shoes.

In the equation \(35x + 55y\), where:

  • \(x\) represents the number of pairs of shoes,
  • \(y\) represents the number of jerseys,
  • \(35\) is the cost per pair of shoes,
  • \(55\) is the cost per jersey.

Antoine spends $35 per pair of shoes.

Consider the expression: (16−12)2+5(8+22)53−(1+4)2
(1 point)
What is the simplified numerator?

To simplify the expression \((16−12)^2 + 5(8+22)53−(1+4)^2\), we'll break it down step by step.

  1. Calculate \(16 - 12\): \[ 16 - 12 = 4 \]

  2. Now square it: \[ (4)^2 = 16 \]

  3. Calculate \(8 + 22\): \[ 8 + 22 = 30 \]

  4. Multiply by \(5\) and \(53\): \[ 5(30)53 = 150 \times 53 \]

    First calculate \(150 \times 53\): \[ 150 \times 53 = 7950 \]

  5. Now calculate \(1 + 4\): \[ 1 + 4 = 5 \]

  6. Now square it: \[ (5)^2 = 25 \]

  7. Putting it all together for the numerator: The numerator is: \[ 16 + 7950 - 25 \]

  8. Calculate: \[ 16 + 7950 = 7966 \] \[ 7966 - 25 = 7941 \]

Therefore, the simplified numerator is 7941.

Use the Commutative Property of Multiplication to rewrite the algebraic expression: f17⋅h33

(2 points)
⋅

Question 2
Which expression correctly demonstrates the Commutative Property of Addition?(1 point)
Responses

15⋅x⋅4=4+15+x
15⋅x⋅4=4+15+x

x+4+15=15+4+x
x plus 4 plus 15 is equal to 15 plus 4 plus x

15(x+4)=15(x⋅4)
15 times open paren x plus 4 close paren is equal to 15 times open paren x times 4 close paren

15⋅x⋅4=4⋅15⋅x

Question 1

Using the Commutative Property of Multiplication, we can rewrite the expression \( f^{17} \cdot h^{33} \) as: \[ h^{33} \cdot f^{17} \]

This property states that the order in which two numbers are multiplied does not affect the product.

Question 2

The expression that correctly demonstrates the Commutative Property of Addition is: \[ x + 4 + 15 = 15 + 4 + x \]

This shows that the sum remains the same regardless of the order of the addends.

Summary of Answers

  1. Rewriting: \( h^{33} \cdot f^{17} \)
  2. Commutative Property of Addition: \( x + 4 + 15 = 15 + 4 + x \)