By simple trigonometry on a plane:
θ=48 minutes (angle of depression)
h=75'
distance = 75/tan(48')
=75/0.01396
=5371.1 feet away
=1.02 mile approx.
If you are looking for correction for the curvature of the earth, a more complex calculation will be required.
I a lighthouse is 75 feet tall and boat is out at sea 40 min away, how far is the boaat from the lighthouse. I'm stump on this problem..Help!
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