Hypochlorous acid, HOCl, is a weak acid with Ka = 3.0 × 10-8. Calculate the

Question

pH of a 0.0125 M solution of HOCl.

Answer 1

....................HOCl ==> H^+ + OCl^-
I..................0.0125M.....0...........0
C................ - x...............x...........x
E................0.0125-x.......x...........x
Ka = 3.0 × 10-8 = (H^+)(OCl^-)/(HOCl)
Substitute the E line into the Ka expression and solve for x = (H^+)
Then pH = -log(H^+)
Post your work if you get stuck.