If you would type a little and show your work we could find the answer quickly.
........HOBr ==. H^+ + BrO^-
I.......0.63.....0......0
C........-x.......x.....x
E......0.63-x.....x.....x
Ka = 2.5E-9 = (x)(x)/(0.63-x).
Solve for x, convert to pH, then
pH + OH = pKw = 14. You know pH and pKw, solve for pOH.
Hypobromous acid,HOBr, has acid -ionization constant of 2.5 X 10^-9 at 25 Celsius . What is the pOH of a 0.63 M HOBr solution?
A4.40
B3.87
C5.20
D9.60
E10.13
I'm getting two answers between A or B
1 answer
1 answer