Hydroxyapatite, Ca10(PO4)6(OH)2Ca10(PO4)6(OH)2 , has a solubility constant of Ksp = 2.34×10−592.34×10−59 , and dissociates according to

Question

Hydroxyapatite,  Ca10(PO4)6(OH)2Ca10(PO4)6(OH)2  , has a solubility constant of Ksp =  2.34×10−592.34×10−59 , and dissociates according to

Ca10(PO4)6(OH)2(s) --> 10Ca2+(aq) + 6PO4^3-(aq) + 2OH-(aq)

Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of  Ca2+  in this solution if [OH−] is fixed at  2.80×10−6 M?

I tried the question and got 3.99, but my answer was wrong...pleasee tell me where i went wrong.

DrBob222 · Answer

I can't tell where you went wrong because you didn't show your work. Show your work and I'll find th error.

TS · Answer

((2.34x10^-59)/ (2.80x10^-6)^2 (3/5)^6)^1/16= 3.99