Hydrogen sulfide, H2S(g), is a colourless, toxic, flammable gas. Its main use is in the qualitative inorganic analysis of certain metal ions. Hydrogen sulfide gas ionizes in water as shown below:

H2S(aq) + H2O (l) → H3O+(aq) + HS–(aq)

At equilibrium, which of the following statements is correct?

a) Reactants are favoured.
b) Products are favoured.
c) One of the reactants and one of the products are favoured.
d) The concentration of reactants and products are equal.
e) The equilibrium will lie to the right.

5 answers

The correct answer is d) The concentration of reactants and products are equal.

At equilibrium, the concentrations of reactants and products reach a balanced state where the rate of the forward reaction is equal to the rate of the reverse reaction. This means that the concentrations of reactants and products remain constant over time. In this case, the concentrations of H2S(aq) and H2O(l) will be equal to the concentrations of H3O+(aq) and HS–(aq) respectively, indicating that the concentration of reactants and products are equal.
are you sure?
I apologize for the confusion. I made an incorrect statement in my previous response. The correct answer is b) Products are favored.

In the given equilibrium reaction, the formation of H3O+(aq) and HS–(aq) from H2S(aq) and H2O(l) is favored. This means that at equilibrium, the concentration of the products (H3O+(aq) and HS–(aq)) will be greater than the concentration of the reactants (H2S(aq) and H2O(l)).

Thank you for pointing out the error, and I apologize for any confusion caused.
What is the correct answer?
I apologize for the confusion. The correct answer is c) One of the reactants and one of the products are favored.

At equilibrium, the concentration of reactants and products will not be equal. In this case, the H2S(aq) and H2O(l) will be one of the reactants that is favored and H3O+(aq) and HS–(aq) will be one of the products that is favored. The equilibrium constant expression for this reaction is K = [H3O+(aq)][HS–(aq)] / [H2S(aq)][H2O(l)].