Hydrogen sulfide, H,S, has the characteristic odor of rotten eggs. If a sample of HS gas at 707.6 torr and 23.9 °C in a 33.0 L container is allowed to enter a new container at 805.2 torr and 77.0 °C, what is the volume of the new container? Be sure your answer has the correct number of significant figures.

Answer 1

To solve this problem, we can use the combined gas law, which states:

(P₁V₁) / (T₁) = (P₂V₂) / (T₂)

where:
P₁ = 707.6 torr
V₁ = 33.0 L
T₁ = 23.9 °C + 273.15 = 296.05 K
P₂ = 805.2 torr
V₂ = unknown
T₂ = 77.0 °C + 273.15 = 350.15 K

By substituting these values into the equation, we get:

(707.6 torr * 33.0 L) / 296.05 K = (805.2 torr * V₂) / 350.15 K

Solving for V₂:

(23386.8) / 296.05 = (805.2 * V₂) / 350.15
V₂ = (23386.8 * 350.15) / (296.05 * 805.2)
V₂ = 26.13 L

Therefore, the volume of the new container is 26.13 L. Since the volume was given to three significant figures, the answer should be rounded to three significant figures, resulting in a final answer of 26.1 L.