In the reaction provided, hydrogen selenite (H₂Se) acts as the acid and donates a proton (H⁺) to water (H₂O), which acts as the base. The resulting products are the conjugate base, selenide ion (SeH⁻), and the conjugate acid, hydronium ion (H₃O⁺). In the context of the periodic table, hydrogen selenite behaves as an acid because it contains selenium, which is a chalcogen and can readily donate protons due to its relatively low electronegativity compared to oxygen (in water), allowing it to lose hydrogen ions easily. Additionally, the presence of a hydrogen atom bonded to selenium suggests a propensity to release that hydrogen as a proton in aqueous solution.
Hydrogen selenite (H2Se +H2O ___SeH-+H3O+
In 3-5 sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use patterns in the periodic table to explain why the substance you identified acted as the acid and the base in this reaction
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