Hydrogen selenide ( ) reacts with water according to the following equation.

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use the periodic table to explain
why each substance acted as the acid or the base in this reaction.

1 answer

In the reaction between hydrogen selenide (H₂Se) and water (H₂O), hydrogen selenide acts as the acid, while water functions as the base. This is because hydrogen selenide donates a proton (H⁺) to water, forming the conjugate base selenide ion (Se²⁻) and the conjugate acid hydronium ion (H₃O⁺).

According to the Brønsted-Lowry acid-base theory, an acid is a proton donor, and a base is a proton acceptor. Hydrogen selenide, containing the relatively electronegative selenium (Se), has a tendency to release protons, categorizing it as an acid. Water, being neutral and able to accept a proton to form hydronium, serves as the base in this equation.

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