H2O2(aq) + 2H+(aq) + 2MnO4-(aq) --> 2H2O(l) + 2Mn2+(aq) + O2(g)
Mass percent of H2O2 = (1.00 g H2O2/1.00 g solution) x 100% = 100%
Hydrogen peroxide, H2O2, solution can be purchased in drug stores and used as an antiseptic. A sample of such a solution weighing 1.00 grams was acidified with sulfuric acid and titrated with .02000 M solution of KMnO4. The unbalanced reaction is H2O2(aq) + MnO4-(aq)--> O2(g)+Mn=2(aq)
The titration required 17.60ml of KMnO4 solution. What is the mass percent of H2O2 in the original solution? (balance the equation first.)
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