2HI ==> H2 + I2
K = 2E-3 = (H2)(I2)/(HI)^2
You look at K. With a small number you know the numerator must be small and the denominator must be large. That's the only way you can have a value less than 1. Therefore, you know that H2 and I2 must be small and HI must be large (relatively speaking). So HI must predominate.
Hydrogen iodide reacts with itself to give hydrogen and iodine. The equilibrium constant is about
2.0 x 10─3 at a particular temperature. If you were to place some hydrogen iodide in a container and
seal the container, what would you expect to find at equilibrium: mostly hydrogen iodide or mostly
hydrogen and iodine?
1 answer