Hydrogen gas (H2) is generated by the following reaction.

Ca(s) + 2 HCl(aq) → CaCl2(aq) + H2(g);
ΔH = −542.7 kJ/mol

When this reaction takes place in a cylinder (fitted with a piston) containing 1.000 mol Ca(s), 542.7 kJ heat is lost to the surroundings. Because a gas is generated, work is done by the system against a constant pressure of 1.140 atm. If the internal energy decreases by 545.53 kJ,

what is the change in the volume of the system in liters?

1 answer

dE = q + w
Substitute dE and q and solve for w (in joules).
Convert to L*atm knowing that 1 L*atm = 101.325 J.
Then w = -pdV and solve for dV.
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