Hydrogen bromide breaks down into diatomic hydrogen and bromine in the reaction shown.

1 answer

The decomposition of hydrogen bromide (HBr) into diatomic hydrogen (Hâ‚‚) and bromine (Brâ‚‚) can be represented by the following chemical equation:

\[ 2 , \text{HBr} , (g) \rightarrow \text{H}_2 , (g) + \text{Br}_2 , (g) \]

In this reaction, two moles of hydrogen bromide gas decompose to form one mole of diatomic hydrogen gas and one mole of diatomic bromine gas. This process may occur under certain conditions, such as high temperatures or in the presence of a catalyst.