Hydrogen and Oxygen react to form water according to the following equation

2H2 + O2 (arrow) 2H2O
If 3dm^3 of oxygen is used what volume of water is produced?

1 answer

The balanced chemical equation for the reaction of hydrogen and oxygen to form water is:

\[ 2H_2 + O_2 \rightarrow 2H_2O \]

From this equation, we can see that 1 volume of \( O_2 \) produces 2 volumes of \( H_2O \). Thus, for every 1 cubic decimeter (dm³) of \( O_2 \), 2 cubic decimeters (dm³) of \( H_2O \) are produced.

If 3 dm³ of \( O_2 \) is used, we can calculate the volume of water produced:

\[ \text{Volume of } H_2O = 3 , \text{dm}^3 , O_2 \times \frac{2 , \text{dm}^3 , H_2O}{1 , \text{dm}^3 , O_2} = 6 , \text{dm}^3 , H_2O \]

Therefore, the volume of water produced is 6 dm³.