To calculate the total bond energy of the products in the reaction between hydrogen (H₂) and iodine (I₂) to produce hydroiodic acid (HI), we consider the bonds that are formed in the products.
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Balanced chemical reaction: The reaction can be shown as:
\[ H_2(g) + I_2(g) \rightarrow 2 HI(g) \]
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Bonds in the products: In the products, there are 2 molecules of hydroiodic acid (HI). Each HI molecule has one H-I bond.
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Bond energy of H-I bond: The bond energy is the energy required to break a bond between atoms. For HI, the typical bond energy is approximately \(298 , \text{kJ/mol}\).
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Calculating the total bond energy in the products: Since there are 2 moles of HI produced, the total bond energy for the 2 H-I bonds is:
\[ \text{Total bond energy} = 2 \times \text{Bond energy of H-I} = 2 \times 298 , \text{kJ/mol} = 596 , \text{kJ/mol} \]
Therefore, the total bond energy in the products of the reaction (2 molecules of HI) is \(596 , \text{kJ/mol}\).