C = 2πr = 2*3.14*(30/2)
(C * 33.3)/100 = m traveled
hw do l wrk ths out: A record has a diameter of 30cm and rotates at 33 n 1/3 revolution per minute. Hw far does a point on the edge of the record travel in a minute? (use the 3,4 for pie n gve answer in metres
3 answers
A disc has a diameter of 30 cm and rotates at 331/3 revolutions per minute.how far does a point on the edge of the disc travel in a minute?ues the value 3.14 for π and give your answer in metres.
The radius of the disc is half of the diameter, which is 15 cm or 0.15 m.
The circumference of the disc is C = πd = 3.14 x 0.3 m = 0.942 m.
The distance traveled by a point on the edge of the disc in one revolution is equal to the circumference of the disc, which is 0.942 m.
In one minute, the disc makes 33 1/3 revolutions, so the distance traveled by a point on the edge of the disc in one minute is:
distance = 0.942 m/rev x 33.33 rev/min = 31.4 m/min
Therefore, a point on the edge of the disc travels 31.4 meters in one minute.
The circumference of the disc is C = πd = 3.14 x 0.3 m = 0.942 m.
The distance traveled by a point on the edge of the disc in one revolution is equal to the circumference of the disc, which is 0.942 m.
In one minute, the disc makes 33 1/3 revolutions, so the distance traveled by a point on the edge of the disc in one minute is:
distance = 0.942 m/rev x 33.33 rev/min = 31.4 m/min
Therefore, a point on the edge of the disc travels 31.4 meters in one minute.