Asked by Writeacher
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Posted by Ashley on Thursday, January 18, 2007 at 6:51pm.
px+qy=r 2px-qy=2r find the solution.
For Further Reading
math - bobpursley, Thursday, January 18, 2007 at 7:09pm
There are five unknowns here: p, q, r, x, y
If p, x, q, and y are unknowns, then the equation is not solvable. If p, q, and r are constants, then add the two equations
px+ qy=r
px -qy=r
adding
2px=2r
x= r/p then solve for y, which has to be zero, or q is zero.
As it is, the equation systems cannot be solved.
Posted by Ashley on Thursday, January 18, 2007 at 6:51pm.
px+qy=r 2px-qy=2r find the solution.
For Further Reading
math - bobpursley, Thursday, January 18, 2007 at 7:09pm
There are five unknowns here: p, q, r, x, y
If p, x, q, and y are unknowns, then the equation is not solvable. If p, q, and r are constants, then add the two equations
px+ qy=r
px -qy=r
adding
2px=2r
x= r/p then solve for y, which has to be zero, or q is zero.
As it is, the equation systems cannot be solved.
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