Please don't use caps. It makes the question difficult to read.
mL x M = mL x M
mL x 4.00 = 30.0 x 0.800
mL HNO3 stock = (30.0 x 0.800/4.00) = 6.00 mL.
So, measure 6.0 mL of the stock 4.00 M HNO3 and add enough water to make 30.0 mL final volume. That will be very close to 24 mL (30.0-6.0 = 24.0 mL) of water.
HOW YOU PREPARE 30.0ML OF 0.800M HNO3 FROM A STOCK SOLUTION OF 4.OOM HNO3? WHAT SOLUTION IN ML OF THE 4.OOM HNO3 SOLUTION WILL YOU NEED?
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