how would your calculation of the molarity of KMnO4 be affected if you had added twice as much sulfuric acid and water as was called for in the procedure?

Answer 1

4 KMnO4(aq) + 6 H2SO4(aq) = 2 K2SO4(aq) + 4 MnSO4(aq) + 6 H2O(l) + 5O2(g)

That would depend on what your limiting reagent is. If it was KMnO4, then the calculation should not change. If it was H2SO4, the calculation will change according to volume etc
However, since adding water will change the volume, the calculations should change as well