How would you write the equation of a line that would be parallel to y = -3x -2, but not share any points. * 1 point y = 3x - 2y = -3x - 2 y = 3x + 8 y = -3x + 8

1 answer

To write the equation of a line that is parallel to the line given by the equation \( y = -3x - 2 \), we need to keep the same slope. The slope of the given line is -3.

Thus, a line that is parallel would also have a slope of -3. The general form of the equation for a line is:

\[ y = mx + b \]

where \( m \) is the slope and \( b \) is the y-intercept. Since we want the parallel line not to share any points with the original line, we need to choose a different y-intercept.

Among the options provided:

  1. \( y = 3x - 2 \) (not parallel, slope = 3)
  2. \( y = -3x - 2 \) (same line, slope = -3)
  3. \( y = 3x + 8 \) (not parallel, slope = 3)
  4. \( y = -3x + 8 \) (parallel, slope = -3)

The correct choice for a parallel line that does not share any points with the original line \( y = -3x - 2 \) is:

\( y = -3x + 8 \).